2x^2-5x+42=0

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Solution for 2x^2-5x+42=0 equation:


Simplifying
2x2 + -5x + 42 = 0

Reorder the terms:
42 + -5x + 2x2 = 0

Solving
42 + -5x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
21 + -2.5x + x2 = 0

Move the constant term to the right:

Add '-21' to each side of the equation.
21 + -2.5x + -21 + x2 = 0 + -21

Reorder the terms:
21 + -21 + -2.5x + x2 = 0 + -21

Combine like terms: 21 + -21 = 0
0 + -2.5x + x2 = 0 + -21
-2.5x + x2 = 0 + -21

Combine like terms: 0 + -21 = -21
-2.5x + x2 = -21

The x term is -2.5x.  Take half its coefficient (-1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
-2.5x + 1.5625 + x2 = -21 + 1.5625

Reorder the terms:
1.5625 + -2.5x + x2 = -21 + 1.5625

Combine like terms: -21 + 1.5625 = -19.4375
1.5625 + -2.5x + x2 = -19.4375

Factor a perfect square on the left side:
(x + -1.25)(x + -1.25) = -19.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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